\documentclass[12pt]{article} \usepackage{amsfonts} %\documentstyle[12pt,amsfonts]{article} %\documentstyle{article} \setlength{\topmargin}{-.5in} \setlength{\oddsidemargin}{0 in} \setlength{\evensidemargin}{0 in} \setlength{\textwidth}{6.5truein} \setlength{\textheight}{8.5truein} %\input ../basicmath/basicmathmac.tex % %\input ../adgeomcs/lamacb.tex \input ../adgeomcs/mac.tex \input ../adgeomcs/mathmac.tex \def\fseq#1#2{(#1_{#2})_{#2\geq 1}} \def\fsseq#1#2#3{(#1_{#3(#2)})_{#2\geq 1}} \def\qleq{\sqsubseteq} % \begin{document} \begin{center} \fbox{{\Large\bf Fall, 2003 \hspace*{0.4cm} CIS 610}}\\ \vspace{1cm} {Advanced geometric methods\\ \vspace{0.5cm} Homework 3}\\[10pt] November 11, 2003; Due November 25, beginning of class\\ \end{center} You may work in groups of 2 or 3. Please, write up your solutions as clearly and concisely as possible. Be rigorous! You will have to present your solutions of the problems during a special problem session. \vspace{0.5cm} ``A problems'' are for practice only, and should not be turned in. \vspace {0.5cm}\noindent {\bf Problem A1.} (1) Given a unit vector $(-\sin\theta, \cos\theta)$, prove that the Householder matrix determined by the vector $(-\sin\theta, \cos\theta)$ is % %\medskip \[\matta{\cos 2\theta}{\sin 2\theta} {\sin 2\theta}{-\cos 2\theta}. \] % %\medskip\noindent Give a geometric interpretation (i.e., why the choice $(-\sin\theta, \cos\theta)$?). \medskip (2) Given any matrix % %\medskip \[A = \matta{a}{b}{c}{d},\] % %\medskip\noindent prove that there is a Householder matrix $H$ such that $AH$ is lower triangular, i.e., % %\medskip \[AH = \matta{a'}{0}{c'}{d'}\] % %\medskip\noindent for some $a', c', d'\in \reals$. \vspace{0.5cm}\noindent {\bf Problem A2}. Given a Euclidean space $E$ of dimension $n$, if $h$ is a reflection about some hyperplane orthogonal to a nonnull vector $\novect{u}$ and $f$ is any isometry, prove that $f\circ h \circ f^{-1}$ is the reflection about the hyperplane orthogonal to $f(\novect{u})$. \vspace{0.5cm}\noindent {\bf Problem A3}. Let $E$ be a Euclidean space of dimension $n = 2$. Prove that given any two unit vectors $\novect{u_1}, \novect{u_2} \in E$ (unit means that $\smnorme{\novect{u_1}} = \smnorme{\novect{u_2}} = 1$), there is a unique rotation $r$ such that \[r(\novect{u_1}) = \novect{u_2}.\] \medskip Prove that there is a rotation mapping the pair $\pairt{\novect{u_1}}{\novect{u_2}}$ to the pair $\pairt{\novect{u_3}}{\novect{u_4}}$ iff there is a rotation mapping the pair $\pairt{\novect{u_1}}{\novect{u_3}}$ to the pair $\pairt{\novect{u_2}}{\novect{u_4}}$ (all vectors being unit vectors). \vspace {0.5cm} ``B problems'' must be turned in. \vspace {0.5cm}\noindent {\bf Problem B1 (30 pts).} This problem is a warm-up for the next problem. %\medskip Consider the set of matrices of the form %\medskip \[\matta{0}{-a}{a}{0},\] % %\medskip\noindent where $a\in \reals$. \medskip (a) Show that these matrices are invertible when $a\not=0$ (give the inverse explicitly). Given any two such matrices $A, B$, show that $AB = BA$. Describe geometrically the action of such a matrix on points in the affine plane $\affreal^2$, with its usual Euclidean inner product. Verify that this set of matrices is a vector space isomorphic to $(\reals, +)$. This vector space is denoted by $\mfrac{so}(2)$. \medskip (b) Given an $n\times n$ matrix $A$, we define the {\it exponential\/} $e^A$ as \[e^A = I_n + \sum_{k\geq 1} \frac{A^k}{k!},\] where $I_n$ denotes the $n\times n$ identity matrix. It can be shown rigorously that this power series is indeed convergent for every $A$ (over $\reals$ or $\complex$), so that $e^A$ makes sense (and you do not have to prove it!). \medskip Given any matrix % %\medskip \[A = \matta{0}{-\theta}{\theta}{0},\] % %\medskip\noindent prove that % %\medskip \[e^A = \cos\theta \matta{1}{0}{0}{1} + \sin\theta\matta{0}{-1}{1}{0} = \matta{\cos\theta}{-\sin\theta}{\sin\theta}{\cos\theta}.\] % %\medskip\noindent \hint Check that % %\medskip \[\matta{0}{-\theta}{\theta}{0} = \theta\matta{0}{-1}{1}{0}\quad\hbox{and}\quad \matta{0}{-\theta}{\theta}{0}^2 = -\theta^2\matta{1}{0}{0}{1},\] % %\medskip\noindent and use the power series for $\cos\theta$ and $\sin\theta$. %\medskip Conclude that the exponential map provides a surjective map $\mapdef{\exp}{{\mfrac{so}}(2)}{\mSO{2}}$ from $\mfrac{so}(2)$ onto the group $\mSO{2}$ of plane rotations. Is this map injective? How do you need to restrict $\theta$ to get an injective map? \medskip \remark By the way, $\mfrac{so}(2)$ is the {\it Lie algebra\/} of the (Lie) group $\mSO{2}$. \endremark \medskip (c) Consider the set $\mU{1}$ of complex numbers of the form $\cos\theta + i\sin\theta$. Check that this is a group under multiplication. Assuming that we use the standard affine frame for the affine plane $\affreal^2$, every point $(x, y)$ corresponds to the complex number $z = x + iy$, and this correspondence is a bijection. Then, every $\alpha = \cos\theta + i\sin\theta\in \mU{1}$ induces the map $\mapdef{R_\alpha}{\affreal^2}{\affreal^2}$ defined such that \[R_\alpha(z) = \alpha z.\] Prove that $R_{\alpha}$ is the rotation of matrix % %\medskip \[\matta{\cos\theta}{-\sin\theta}{\sin\theta}{\cos\theta}.\] % %\medskip\noindent Prove that the map $\mapdef{R}{\mU{1}}{\mSO{2}}$ defined such that $R(\alpha) = R_{\alpha}$ is an isomorphism. Deduce that topologically, $\mSO{2}$ is a circle. Using the exponential map from $\reals$ to $\mU{1}$ defined such that $\theta \mapsto e^{i\theta} = \cos\theta + i\sin\theta$, prove that there is a surjective homomorphism from $(R, +)$ to $\mSO{2}$. What is the connection with the exponential map from $\mfrac{so}(2)$ to $\mSO{2}$? \vspace {0.5cm}\noindent {\bf Problem B2 (60 pts).} \medskip (a) Recall that the coordinates of the cross product $\novect{u}\times\novect{v}$ of two vectors $\novect{u} = (u_1, u_2, u_3)$ and $\novect{v} = (v_1, v_2, v_3)$ in $\reals^3$ are \[(u_2v_3 - u_3v_2,\, u_3v_1 - u_1v_3,\, u_1v_2 - u_2v_1).\] \medskip Letting $U$ be the matrix % %\medskip \[U = \mattc{0}{-u_3}{u_2}{u_3}{0}{-u_1}{-u_2}{u_1}{0},\] % %\medskip\noindent check that the coordinates of the cross product $\novect{u}\times\novect{v}$ are given by % %\medskip \[\mattc{0}{-u_3}{u_2}{u_3}{0}{-u_1}{-u_2}{u_1}{0}\trivec{v_1}{v_2}{v_3} = \trivec{u_2v_3 - u_3v_2}{u_3v_1 - u_1v_3}{u_1v_2 - u_2v_1}.\] \medskip (b) Show that the set of matrices of the form % %\medskip \[U = \mattc{0}{-u_3}{u_2}{u_3}{0}{-u_1}{-u_2}{u_1}{0}\] % %\medskip\noindent is a vector space isomorphic to $(\reals^3 +)$. This vector space is denoted by $\mfrac{so}(3)$. Show that such matrices are never invertible. Find the kernel of the linear map associated with a matrix $U$. Describe geometrically the action of the linear map defined by a matrix $U$. Show that when restricted to the plane orthogonal to $\novect{u} = (u_1, u_2, u_3)$ through the origin, it is a rotation by $\pi/2$. \medskip (c) Consider the map $\mapdef{\psi}{(\reals^3,\times)}{{\mfrac{so}}(3)}$ defined by the formula % \[\psi(u_1, u_2, u_3) = \mattc{0}{-u_3}{u_2}{u_3}{0}{-u_1}{-u_2}{u_1}{0}.\] % %\medskip\noindent For any two matrices $A, B\in \mfrac{so}(3)$, defining $[A,\, B]$ as \[[A,\, B] = AB - BA,\] verify that \[\psi(\novect{u}\times\novect{v}) = [\psi(\novect{u}),\, \psi(\novect{v})].\] %\medskip Show that $[-,\, -]$ is not associative. Show that $[A,\, A] = 0$, and that the so-called {\it Jacobi identity\/} holds: \[[A,\, [B,\, C]] + [C,\, [A,\, B]] + [B,\, [C,\, A]] = 0.\] Show that $[A\, B]$ is bilinear (linear in both $A$ and $B$). %\medskip \remark $[A,\, B]$ is called a {\it Lie bracket\/}, and under this operation, the vector space $\mfrac{so}(3)$ is called a {\it Lie algebra\/}. In fact, it is the Lie algebra of the (Lie) group $\mSO{3}$. \endremark \medskip (d) For any matrix \[A = \mattc{0}{-c}{b}{c}{0}{-a}{-b}{a}{0},\] % %\medskip\noindent letting $\theta = \sqrt{a^2 + b^2 + c^2}$ and % \[B = \mattc{a^2}{ab}{ac}{ab}{b^2}{bc}{ac}{bc}{c^2},\] % %\medskip\noindent prove that \[\eqaligneno{ A^2 &= -\theta^2 I + B,\cr AB &= BA = 0.\cr }\] From the above, deduce that \[A^3 = -\theta^2 A,\] and for any $k\geq 0$, \[\eqaligneno{ A^{4k + 1} &= \theta^{4k} A,\cr A^{4k + 2} &= \theta^{4k} A^2,\cr A^{4k + 3} &= -\theta^{4k + 2} A,\cr A^{4k + 4} &= -\theta^{4k + 2} A^2.\cr }\] Then prove that the exponential map $\mapdef{\exp}{{\mfrac{so}}(3)}{\mSO{3}}$ is given by \[\exp{A} = e^A = \cos\theta\, I_3 + \frac{\sin\theta}{\theta} A + \frac{(1 - \cos\theta)}{\theta^2} B,\] or, equivalently, by \[e^A = I_3 + \frac{\sin\theta}{\theta} A + \frac{(1 - \cos\theta)}{\theta^2} A^2,\] if $\theta \not= k2\pi$ ($k\in\integs$), with $\exp(0_3) = I_3$. %\medskip \remark This formula is known as Rodrigues's formula (1840). \endremark \medskip (e) Prove that $\exp{A}$ is a rotation of axis $(a, b, c)$ and of angle $\theta = \sqrt{a^2 + b^2 + c^2}$. %\medskip \hint Check that $e^A$ is an orthogonal matrix of determinant $+1$, etc., or look up any textbook on kinematics or classical dynamics! \medskip (f) Prove that the exponential map $\mapdef{\exp}{{\mfrac{so}}(3)}{\mSO{3}}$ is surjective. Prove that if $R$ is a rotation matrix different from $I_3$, letting $\novect{\omega} = (a, b, c)$ be a unit vector defining the axis of rotation, if $\trace(R) = -1$, then % %\medskip \[(\exp(R))^{-1} = \left\{\pm\pi\mattc{0}{-c}{b}{c}{0}{-a}{-b}{a}{0}\right\},\] % %\medskip\noindent and if $\trace(R) \not= -1$, then \[(\exp(R))^{-1} = \left\{\frac{\theta}{2\sin\theta}(R - R^T)\ \bigg|\ 1 + 2\cos\theta = \trace(R)\right\}.\] %\medskip (Recall that $\trace(R) = r_{1\, 1} + r_{2\, 2} + r_{3\, 3}$, the {\it trace\/} of the matrix $R$). Note that both $\theta$ and $2\pi-\theta$ yield the same matrix $\exp(R)$. \vspace {0.5cm}\noindent {\bf Problem B3 (30 pts).} Given $p$ vectors $(\novect{u_1},\ldots,\novect{u_p})$ in a Euclidean space $E$ of dimension $n\geq p$, the {\it Gram determinant (or Gramian)\/} of the vectors $(\novect{u_1},\ldots,\novect{u_p})$ is the determinant %\medskip \[\Gram(\novect{u_1},\ldots,\novect{u_p}) = \gramdet{u}{p}.\] \medskip (1) Prove that \[\Gram(\novect{u_1},\ldots,\novect{u_n}) = \lambda_{\vectorsmal{E}}(\novect{u_1},\ldots,\novect{u_n})^2.\] %\medskip \hint By a previous problem, if $(\novect{e_1},\ldots,\novect{e_n})$ is an orthonormal basis of $E$ and $A$ is the matrix of the vectors $(\novect{u_1},\ldots,\novect{u_n})$ over this basis, \[\det(A)^2 = \det(\transpos{A}A) = \det(\dotprod{A_i}{A_j}),\] where $A_i$ denotes the $i$th column of the matrix $A$, and $(\dotprod{A_i}{A_j})$ denotes the $n\times n$ matrix with entries $\dotprod{A_i}{A_j}$. \medskip (2) Prove that \[\smnorme{\novect{u_1}\times\cdots\times\novect{u_{n-1}}}^2 = \Gram(\novect{u_1},\ldots,\novect{u_{n-1}}).\] %\medskip \hint Letting $\novect{w} = \novect{u_1}\times\cdots\times\novect{u_{n-1}}$, observe that \[\lambda_{\vectorsmal{E}}(\novect{u_1},\ldots,\novect{u_{n-1}}, \novect{w}) = \pairt{\novect{w}}{\novect{w}} = \smnorme{\novect{w}}^2,\] and show that \[ \eqaligneno{ \smnorme{\novect{w}}^4 &= \lambda_{\vectorsmal{E}}(\novect{u_1},\ldots,\novect{u_{n-1}}, \novect{w})^2 = \Gram(\novect{u_1},\ldots,\novect{u_{n-1}}, \novect{w}) \cr &= \Gram(\novect{u_1},\ldots,\novect{u_{n-1}})\smnorme{\novect{w}}^2.\cr } \] \vspace {0.5cm}\noindent {\bf Problem B4 (50 pts).} \label{pb7.11} Given a Euclidean space $E$, let $U$ be a nonempty affine subspace of $E$, and let $a$ be any point in $E$. We define the {\it distance $d(a, U)$\/} of $a$ to $U$ as \[d(a, U) = \inf\{\smnorme{\libvecbo{a}{b}}\ |\ b\in U\}.\] \medskip (a) Prove that the affine subspace $\orthog{U}_a$ defined such that \[\orthog{U}_a = a + \orthog{\vector{U}}\] intersects $U$ in a single point $b$ such that $d(a, U) = \smnorme{\libvecbo{a}{b}}$. %\medskip \hint Recall the discussion after Lemma 2.11.2. \medskip (b) Let $(a_0, \ldots, a_p)$ be a frame for $U$ (not necessarily orthonormal). Prove that \[d(a, U)^2 = \frac{\Gram(\libvecbo{a_0}{a}, \libvecbo{a_0}{a_1}, \ldots, \libvecbo{a_0}{a_p})} {\Gram(\libvecbo{a_0}{a_1}, \ldots, \libvecbo{a_0}{a_p})}.\] %\medskip \hint $\Gram$ is unchanged when a linear combination of other vectors is added to one of the vectors, and thus \[{\Gram(\libvecbo{a_0}{a}, \libvecbo{a_0}{a_1}, \ldots, \libvecbo{a_0}{a_p})} = {\Gram(\libvecbo{b}{a}, \libvecbo{a_0}{a_1}, \ldots, \libvecbo{a_0}{a_p})},\] where $b$ is the unique point defined in question (a). \medskip (c) If $D$ and $D'$ are two lines in $E$ that are not coplanar, $a, b\in D$ are distinct points on $D$, and $a', b' \in D'$ are distinct points on $D'$, prove that if $d(D, D')$ is the shortest distance between $D$ and $D'$ (why does it exist?), then \[d(D, D')^2 = \frac{\Gram(\libvecbo{a}{a'}, \libvecbo{a}{b}, \libvecbo{a'}{b'})} {\Gram(\libvecbo{a}{b}, \libvecbo{a'}{b'})}.\] \vspace {0.5cm}\noindent {\bf Problem B5 (30 pts).} In $\eucreal^3$, consider the closed convex set (cone), $A$, defined by the inequalities \[ x\geq 0,\quad y\geq 0,\quad z\geq 0, \quad z^2 \leq xy, \] and let $D$ be the line given by $x = 0, z = 1$. Prove that $D \cap A = \emptyset$, both $A$ and $D$ are convex and closed, yet every plane containing $D$ meets $A$. Therefore, $A$ and $D$ give another counter-example to the Hahn-Banach theorem where $A$ is closed (one cannot relax the hypothesis that $A$ is open). \vspace {0.5cm}\noindent {\bf Problem B6 (30 pts).} In $\eucreal^n$, consider the polar duality $A \mapsto A^*$, with respect to the origin, $O$. \medskip (i) For any nonempty subsets, $A, B\subseteq \eucreal^n$, prove the following properties: \begin{enumerate} \item[(a)] $A^{*} = A^{***}$. \item[(b)] For any $\lambda \not= 0$, we have $(\lambda A)^* = (1/\lambda) A^*$. \item[(c)] $(A\cup B)^* = A^* \cap B^*$. \item[(d)] $A^{**} = \overline{\chullb{A\cup \{O\}}}$, the topological closure of the convex hull of $A$ and the origin. \item[(e)] If $A$ and $B$ are closed, convex and both contain $O$, then $(A\cap B)^* = \overline{\chullb{A^* \cup B^*}}$, the topological closure of the convex hull of $A^* \cup B^*$. \end{enumerate} (ii) If $A, B\subseteq \eucreal^n$, for any $\lambda$, the set \[(1 - \lambda) A + \lambda B = \{(1 - \lambda)a + \lambda b \mid a\in A,\> b\in B\} \] is the {\it Minkowski sum\/} of $A$ and $B$. Assume that $0 \leq \lambda \leq 1$. Check that $(1 - \lambda) A + \lambda B$ is convex if $A$ and $B$ are convex. Prove that $(1 - \lambda) A + \lambda B$ is a polytope if $A$ and $B$ are polytopes. \medskip (iii) ({\bf Extra Credit\/}) The Minkowski sum can be viewed as a way of interpolating between two polytopes and gives a way of {\it morphing\/} one polytope to another. The vertices of \\ $(1 - \lambda) A + \lambda B$ are convex combinations of the vertices of $A$ and $B$. However, not all of these convex combinations are vertices. Investigate (in $\eucreal^3$) practical algorithms for displaying the result of morphing polytopes using the Minkowski sum (You may want to begin with the case of polygons in $\eucreal^2$.) \vspace{0.5cm}\noindent {\bf TOTAL: 230 points.} \end{document}